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143=2x+x^2
We move all terms to the left:
143-(2x+x^2)=0
We get rid of parentheses
-x^2-2x+143=0
We add all the numbers together, and all the variables
-1x^2-2x+143=0
a = -1; b = -2; c = +143;
Δ = b2-4ac
Δ = -22-4·(-1)·143
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-24}{2*-1}=\frac{-22}{-2} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+24}{2*-1}=\frac{26}{-2} =-13 $
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